(a^2)+7a-9=0

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Solution for (a^2)+7a-9=0 equation: 



(a^2)+7a-9=0

a = 1; b = 7; c = -9;
Δ = b2-4ac
Δ = 72-4·1·(-9)
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{85}}{2*1}=\frac{-7-\sqrt{85}}{2}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{85}}{2*1}=\frac{-7+\sqrt{85}}{2}
$

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